Mercurial > public > mercurial-scm > hg
annotate mercurial/hbisect.py @ 5909:f45f7390c1c5
strip: calculate list of extra nodes to save and pass it to changegroupsubset
When we remove revision N from the repository, all revisions >= N are
affected: either it's a descendant from N and will also be removed, or
it's not a descendant of N and will be renumbered.
As a consequence, we have to (at least temporarily) remove all filelog
and manifest revisions that have a linkrev >= N, readding some of them
later.
Unfortunately, it's possible to have a revlog with two revisions
r1 and r2 such that r1 < r2, but linkrev(r1) > linkrev(r2). If we try
to strip revision linkrev(r1) from the repository, we'll also lose
revision r2 when we truncate this revlog.
We already use changegroupsubset to create a temporary changegroup
containing the revisions that have to be restored, but that function is
unable to detect that we also wanted to save the r2 in the case above.
So we manually calculate these extra nodes and pass it to changegroupsubset.
This should fix issue764.
author | Alexis S. L. Carvalho <alexis@cecm.usp.br> |
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date | Sat, 19 Jan 2008 18:01:16 -0200 |
parents | 51776e50bc8c |
children | fe8dbbe9520d |
rev | line source |
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1 # changelog bisection for mercurial |
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2 # |
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3 # Copyright 2007 Matt Mackall |
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4 # Copyright 2005, 2006 Benoit Boissinot <benoit.boissinot@ens-lyon.org> |
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5 # Inspired by git bisect, extension skeleton taken from mq.py. |
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6 # |
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7 # This software may be used and distributed according to the terms |
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8 # of the GNU General Public License, incorporated herein by reference. |
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9 |
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10 from i18n import _ |
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11 import hg, util |
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12 |
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13 def bisect(changelog, state): |
5737 | 14 clparents = changelog.parentrevs |
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15 skip = dict.fromkeys([changelog.rev(n) for n in state['skip']]) |
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16 |
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17 def buildancestors(bad, good): |
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18 # only the earliest bad revision matters |
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19 badrev = min([changelog.rev(n) for n in bad]) |
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20 goodrevs = [changelog.rev(n) for n in good] |
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21 # build ancestors array |
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22 ancestors = [[]] * (changelog.count() + 1) # an extra for [-1] |
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23 |
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24 # clear good revs from array |
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25 for node in goodrevs: |
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26 ancestors[node] = None |
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27 for rev in xrange(changelog.count(), -1, -1): |
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28 if ancestors[rev] is None: |
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29 for prev in clparents(rev): |
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30 ancestors[prev] = None |
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31 |
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32 if ancestors[badrev] is None: |
5777 | 33 return badrev, None |
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34 return badrev, ancestors |
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35 |
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36 good = 0 |
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37 badrev, ancestors = buildancestors(state['bad'], state['good']) |
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38 if not ancestors: # looking for bad to good transition? |
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39 good = 1 |
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40 badrev, ancestors = buildancestors(state['good'], state['bad']) |
5777 | 41 bad = changelog.node(badrev) |
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42 if not ancestors: # now we're confused |
5737 | 43 raise util.Abort(_("Inconsistent state, %s:%s is good and bad") |
44 % (badrev, hg.short(bad))) | |
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45 |
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46 # build children dict |
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47 children = {} |
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48 visit = [badrev] |
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49 candidates = [] |
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50 while visit: |
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51 rev = visit.pop(0) |
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52 if ancestors[rev] == []: |
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53 candidates.append(rev) |
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54 for prev in clparents(rev): |
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55 if prev != -1: |
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56 if prev in children: |
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57 children[prev].append(rev) |
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58 else: |
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59 children[prev] = [rev] |
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60 visit.append(prev) |
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61 |
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62 candidates.sort() |
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63 # have we narrowed it down to one entry? |
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64 tot = len(candidates) |
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65 if tot == 1: |
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66 return (bad, 0, good) |
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67 perfect = tot / 2 |
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68 |
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69 # find the best node to test |
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70 best_rev = None |
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71 best_len = -1 |
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72 poison = {} |
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73 for rev in candidates: |
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74 if rev in poison: |
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75 for c in children.get(rev, []): |
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76 poison[c] = True # poison children |
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77 continue |
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78 |
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79 a = ancestors[rev] or [rev] |
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80 ancestors[rev] = None |
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81 |
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82 x = len(a) # number of ancestors |
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83 y = tot - x # number of non-ancestors |
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84 value = min(x, y) # how good is this test? |
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85 if value > best_len and rev not in skip: |
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86 best_len = value |
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87 best_rev = rev |
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88 if value == perfect: # found a perfect candidate? quit early |
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89 break |
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90 |
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91 if y < perfect: # all downhill from here? |
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92 for c in children.get(rev, []): |
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93 poison[c] = True # poison children |
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94 continue |
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95 |
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96 for c in children.get(rev, []): |
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97 if ancestors[c]: |
5774 | 98 ancestors[c] = dict.fromkeys(ancestors[c] + a).keys() |
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99 else: |
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100 ancestors[c] = a + [c] |
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101 |
5737 | 102 assert best_rev is not None |
103 best_node = changelog.node(best_rev) | |
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104 |
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105 return (best_node, tot, good) |