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doctest: bulk-replace string literals with b'' for Python 3 Our code transformer can't rewrite string literals in docstrings, and I don't want to make the transformer more complex.
author Yuya Nishihara <yuya@tcha.org>
date Sun, 03 Sep 2017 14:32:11 +0900
parents bfb38c5cebf4
children 264872544362
comparison
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34130:ada8a19672ab 34131:0fa781320203
25 25
26 _defaultextra = {'branch': 'default'} 26 _defaultextra = {'branch': 'default'}
27 27
28 def _string_escape(text): 28 def _string_escape(text):
29 """ 29 """
30 >>> d = {'nl': chr(10), 'bs': chr(92), 'cr': chr(13), 'nul': chr(0)} 30 >>> d = {b'nl': chr(10), b'bs': chr(92), b'cr': chr(13), b'nul': chr(0)}
31 >>> s = "ab%(nl)scd%(bs)s%(bs)sn%(nul)sab%(cr)scd%(bs)s%(nl)s" % d 31 >>> s = b"ab%(nl)scd%(bs)s%(bs)sn%(nul)sab%(cr)scd%(bs)s%(nl)s" % d
32 >>> s 32 >>> s
33 'ab\\ncd\\\\\\\\n\\x00ab\\rcd\\\\\\n' 33 'ab\\ncd\\\\\\\\n\\x00ab\\rcd\\\\\\n'
34 >>> res = _string_escape(s) 34 >>> res = _string_escape(s)
35 >>> s == util.unescapestr(res) 35 >>> s == util.unescapestr(res)
36 True 36 True
39 text = text.replace('\\', '\\\\').replace('\n', '\\n').replace('\r', '\\r') 39 text = text.replace('\\', '\\\\').replace('\n', '\\n').replace('\r', '\\r')
40 return text.replace('\0', '\\0') 40 return text.replace('\0', '\\0')
41 41
42 def decodeextra(text): 42 def decodeextra(text):
43 """ 43 """
44 >>> sorted(decodeextra(encodeextra({'foo': 'bar', 'baz': chr(0) + '2'}) 44 >>> sorted(decodeextra(encodeextra({b'foo': b'bar', b'baz': chr(0) + b'2'})
45 ... ).iteritems()) 45 ... ).iteritems())
46 [('baz', '\\x002'), ('branch', 'default'), ('foo', 'bar')] 46 [('baz', '\\x002'), ('branch', 'default'), ('foo', 'bar')]
47 >>> sorted(decodeextra(encodeextra({'foo': 'bar', 47 >>> sorted(decodeextra(encodeextra({b'foo': b'bar',
48 ... 'baz': chr(92) + chr(0) + '2'}) 48 ... b'baz': chr(92) + chr(0) + b'2'})
49 ... ).iteritems()) 49 ... ).iteritems())
50 [('baz', '\\\\\\x002'), ('branch', 'default'), ('foo', 'bar')] 50 [('baz', '\\\\\\x002'), ('branch', 'default'), ('foo', 'bar')]
51 """ 51 """
52 extra = _defaultextra.copy() 52 extra = _defaultextra.copy()
53 for l in text.split('\0'): 53 for l in text.split('\0'):