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view rust/hg-cpython/src/utils.rs @ 43422:b9f791090211
rust-cpython: rename PyLeakedRef to PyLeaked
This series will make PyLeaked* behave more like a Python iterator, which
means mutation of the owner object will be allowed and the leaked reference
(i.e. the iterator) will be invalidated instead.
I'll add PyLeakedRef/PyLeakedRefMut structs which will represent a "borrowed"
state, and prevent the underlying value from being mutably borrowed while the
leaked reference is in use:
let shared = self.inner_shared(py);
let leaked = shared.leak_immutable();
{
let leaked_ref: PyLeakedRef<_> = leaked.borrow(py);
shared.borrow_mut(); // panics since the underlying value is borrowed
}
shared.borrow_mut(); // allowed
The relation between PyLeaked* structs is quite similar to RefCell/Ref/RefMut,
but the implementation can't be reused because the borrowing state will have
to be shared across objects having no lifetime relation.
PyLeaked isn't named as PyLeakedCell since it isn't actually a cell in that
leaked.borrow_mut() will require &mut self.
author | Yuya Nishihara <yuya@tcha.org> |
---|---|
date | Sat, 12 Oct 2019 19:10:51 +0900 |
parents | 970978975574 |
children | d738b7a18438 |
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use cpython::{PyDict, PyObject, PyResult, PyTuple, Python}; #[allow(unused)] pub fn print_python_trace(py: Python) -> PyResult<PyObject> { eprintln!("==============================="); eprintln!("Printing Python stack from Rust"); eprintln!("==============================="); let traceback = py.import("traceback")?; let sys = py.import("sys")?; let kwargs = PyDict::new(py); kwargs.set_item(py, "file", sys.get(py, "stderr")?)?; traceback.call(py, "print_stack", PyTuple::new(py, &[]), Some(&kwargs)) }