annotate tests/test-lrucachedict.py @ 39570:f296c0b366c8

util: lower water mark when removing nodes after cost limit reached See the inline comment for the reasoning here. This is a pretty common strategy for garbage collectors, other cache-like primtives. The performance impact is substantial: $ hg perflrucachedict --size 4 --gets 1000000 --sets 1000000 --mixed 1000000 --costlimit 100 ! inserts w/ cost limit ! wall 1.659181 comb 1.650000 user 1.650000 sys 0.000000 (best of 7) ! wall 1.722122 comb 1.720000 user 1.720000 sys 0.000000 (best of 6) ! mixed w/ cost limit ! wall 1.139955 comb 1.140000 user 1.140000 sys 0.000000 (best of 9) ! wall 1.182513 comb 1.180000 user 1.180000 sys 0.000000 (best of 9) $ hg perflrucachedict --size 1000 --gets 1000000 --sets 1000000 --mixed 1000000 --costlimit 10000 ! inserts ! wall 0.679546 comb 0.680000 user 0.680000 sys 0.000000 (best of 15) ! sets ! wall 0.825147 comb 0.830000 user 0.830000 sys 0.000000 (best of 13) ! inserts w/ cost limit ! wall 25.105273 comb 25.080000 user 25.080000 sys 0.000000 (best of 3) ! wall 1.724397 comb 1.720000 user 1.720000 sys 0.000000 (best of 6) ! mixed ! wall 0.807096 comb 0.810000 user 0.810000 sys 0.000000 (best of 13) ! mixed w/ cost limit ! wall 12.104470 comb 12.070000 user 12.070000 sys 0.000000 (best of 3) ! wall 1.190563 comb 1.190000 user 1.190000 sys 0.000000 (best of 9) $ hg perflrucachedict --size 1000 --gets 1000000 --sets 1000000 --mixed 1000000 --costlimit 10000 --mixedgetfreq 90 ! inserts ! wall 0.711177 comb 0.710000 user 0.710000 sys 0.000000 (best of 14) ! sets ! wall 0.846992 comb 0.850000 user 0.850000 sys 0.000000 (best of 12) ! inserts w/ cost limit ! wall 25.963028 comb 25.960000 user 25.960000 sys 0.000000 (best of 3) ! wall 2.184311 comb 2.180000 user 2.180000 sys 0.000000 (best of 5) ! mixed ! wall 0.728256 comb 0.730000 user 0.730000 sys 0.000000 (best of 14) ! mixed w/ cost limit ! wall 3.174256 comb 3.170000 user 3.170000 sys 0.000000 (best of 4) ! wall 0.773186 comb 0.770000 user 0.770000 sys 0.000000 (best of 13) $ hg perflrucachedict --size 100000 --gets 1000000 --sets 1000000 --mixed 1000000 --mixedgetfreq 90 --costlimit 5000000 ! gets ! wall 1.191368 comb 1.190000 user 1.190000 sys 0.000000 (best of 9) ! wall 1.195304 comb 1.190000 user 1.190000 sys 0.000000 (best of 9) ! inserts ! wall 0.950995 comb 0.950000 user 0.950000 sys 0.000000 (best of 11) ! inserts w/ cost limit ! wall 1.589732 comb 1.590000 user 1.590000 sys 0.000000 (best of 7) ! sets ! wall 1.094941 comb 1.100000 user 1.090000 sys 0.010000 (best of 9) ! mixed ! wall 0.936420 comb 0.940000 user 0.930000 sys 0.010000 (best of 10) ! mixed w/ cost limit ! wall 0.882780 comb 0.870000 user 0.870000 sys 0.000000 (best of 11) This puts us ~2x slower than caches without cost accounting. And for read-heavy workloads (the prime use cases for caches), performance is nearly identical. In the worst case (pure write workloads with cost accounting enabled), we're looking at ~1.5us per insert on large caches. That seems "fast enough." Differential Revision: https://phab.mercurial-scm.org/D4505
author Gregory Szorc <gregory.szorc@gmail.com>
date Thu, 06 Sep 2018 18:04:27 -0700
parents 842cd0bdda75
children 8f2c0d1b454c
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1 from __future__ import absolute_import, print_function
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3 import unittest
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4
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5 import silenttestrunner
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6
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7 from mercurial import (
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8 util,
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9 )
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11 class testlrucachedict(unittest.TestCase):
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12 def testsimple(self):
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13 d = util.lrucachedict(4)
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14 self.assertEqual(d.capacity, 4)
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15 d.insert('a', 'va', cost=2)
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16 d['b'] = 'vb'
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17 d['c'] = 'vc'
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18 d.insert('d', 'vd', cost=42)
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19
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20 self.assertEqual(d['a'], 'va')
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21 self.assertEqual(d['b'], 'vb')
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22 self.assertEqual(d['c'], 'vc')
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23 self.assertEqual(d['d'], 'vd')
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24
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25 self.assertEqual(d.totalcost, 44)
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26
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27 # 'a' should be dropped because it was least recently used.
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28 d['e'] = 've'
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29 self.assertNotIn('a', d)
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30 self.assertIsNone(d.get('a'))
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31 self.assertEqual(d.totalcost, 42)
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32
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33 self.assertEqual(d['b'], 'vb')
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34 self.assertEqual(d['c'], 'vc')
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35 self.assertEqual(d['d'], 'vd')
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36 self.assertEqual(d['e'], 've')
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37
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38 # Replacing item with different cost adjusts totalcost.
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39 d.insert('e', 've', cost=4)
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40 self.assertEqual(d.totalcost, 46)
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41
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42 # Touch entries in some order (both get and set).
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43 d['e']
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44 d['c'] = 'vc2'
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45 d['d']
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46 d['b'] = 'vb2'
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47
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48 # 'e' should be dropped now
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49 d['f'] = 'vf'
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50 self.assertNotIn('e', d)
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51 self.assertEqual(d['b'], 'vb2')
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52 self.assertEqual(d['c'], 'vc2')
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53 self.assertEqual(d['d'], 'vd')
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54 self.assertEqual(d['f'], 'vf')
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55
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56 d.clear()
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57 for key in ('a', 'b', 'c', 'd', 'e', 'f'):
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58 self.assertNotIn(key, d)
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59
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60 def testunfull(self):
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61 d = util.lrucachedict(4)
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62 d['a'] = 1
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63 d['b'] = 2
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64 d['a']
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65 d['b']
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66
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67 for key in ('a', 'b'):
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68 self.assertIn(key, d)
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69
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70 def testcopypartial(self):
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71 d = util.lrucachedict(4)
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72 d.insert('a', 'va', cost=4)
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73 d.insert('b', 'vb', cost=2)
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74
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75 dc = d.copy()
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76
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77 self.assertEqual(len(dc), 2)
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78 self.assertEqual(dc.totalcost, 6)
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79 for key in ('a', 'b'):
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80 self.assertIn(key, dc)
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81 self.assertEqual(dc[key], 'v%s' % key)
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82
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83 self.assertEqual(len(d), 2)
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84 for key in ('a', 'b'):
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85 self.assertIn(key, d)
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86 self.assertEqual(d[key], 'v%s' % key)
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87
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88 d['c'] = 'vc'
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89 del d['b']
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90 self.assertEqual(d.totalcost, 4)
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91 dc = d.copy()
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92 self.assertEqual(len(dc), 2)
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93 self.assertEqual(dc.totalcost, 4)
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94 for key in ('a', 'c'):
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95 self.assertIn(key, dc)
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96 self.assertEqual(dc[key], 'v%s' % key)
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97
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98 def testcopyempty(self):
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99 d = util.lrucachedict(4)
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100 dc = d.copy()
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101 self.assertEqual(len(dc), 0)
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102
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103 def testcopyfull(self):
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104 d = util.lrucachedict(4)
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105 d.insert('a', 'va', cost=42)
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106 d['b'] = 'vb'
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107 d['c'] = 'vc'
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108 d['d'] = 'vd'
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109
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110 dc = d.copy()
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111
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112 for key in ('a', 'b', 'c', 'd'):
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113 self.assertIn(key, dc)
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114 self.assertEqual(dc[key], 'v%s' % key)
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115
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116 self.assertEqual(d.totalcost, 42)
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117 self.assertEqual(dc.totalcost, 42)
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118
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119 # 'a' should be dropped because it was least recently used.
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120 dc['e'] = 've'
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121 self.assertNotIn('a', dc)
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122 for key in ('b', 'c', 'd', 'e'):
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123 self.assertIn(key, dc)
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124 self.assertEqual(dc[key], 'v%s' % key)
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125
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126 self.assertEqual(d.totalcost, 42)
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127 self.assertEqual(dc.totalcost, 0)
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128
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129 # Contents and order of original dict should remain unchanged.
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130 dc['b'] = 'vb_new'
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131
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132 self.assertEqual(list(iter(d)), ['d', 'c', 'b', 'a'])
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133 for key in ('a', 'b', 'c', 'd'):
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134 self.assertEqual(d[key], 'v%s' % key)
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135
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136 d = util.lrucachedict(4, maxcost=42)
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137 d.insert('a', 'va', cost=5)
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138 d.insert('b', 'vb', cost=4)
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139 d.insert('c', 'vc', cost=3)
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140 dc = d.copy()
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141 self.assertEqual(dc.maxcost, 42)
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142 self.assertEqual(len(dc), 3)
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143
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144 # Max cost can be lowered as part of copy.
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145 dc = d.copy(maxcost=10)
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146 self.assertEqual(dc.maxcost, 10)
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147 self.assertEqual(len(dc), 2)
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148 self.assertEqual(dc.totalcost, 7)
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149 self.assertIn('b', dc)
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150 self.assertIn('c', dc)
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151
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152 def testcopydecreasecapacity(self):
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153 d = util.lrucachedict(5)
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154 d.insert('a', 'va', cost=4)
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155 d.insert('b', 'vb', cost=2)
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156 d['c'] = 'vc'
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157 d['d'] = 'vd'
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158
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159 dc = d.copy(2)
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160 self.assertEqual(dc.totalcost, 0)
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161 for key in ('a', 'b'):
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162 self.assertNotIn(key, dc)
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163 for key in ('c', 'd'):
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164 self.assertIn(key, dc)
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165 self.assertEqual(dc[key], 'v%s' % key)
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166
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167 dc.insert('e', 've', cost=7)
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168 self.assertEqual(dc.totalcost, 7)
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169 self.assertNotIn('c', dc)
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170 for key in ('d', 'e'):
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171 self.assertIn(key, dc)
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172 self.assertEqual(dc[key], 'v%s' % key)
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173
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174 # Original should remain unchanged.
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175 self.assertEqual(d.totalcost, 6)
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176 for key in ('a', 'b', 'c', 'd'):
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177 self.assertIn(key, d)
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178 self.assertEqual(d[key], 'v%s' % key)
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179
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180 def testcopyincreasecapacity(self):
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181 d = util.lrucachedict(5)
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182 d['a'] = 'va'
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183 d['b'] = 'vb'
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184 d['c'] = 'vc'
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185 d['d'] = 'vd'
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186
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187 dc = d.copy(6)
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188 for key in ('a', 'b', 'c', 'd'):
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189 self.assertIn(key, dc)
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190 self.assertEqual(dc[key], 'v%s' % key)
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191
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192 dc['e'] = 've'
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193 dc['f'] = 'vf'
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194 for key in ('a', 'b', 'c', 'd', 'e', 'f'):
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195 self.assertIn(key, dc)
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196 self.assertEqual(dc[key], 'v%s' % key)
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197
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198 dc['g'] = 'vg'
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199 self.assertNotIn('a', dc)
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200 for key in ('b', 'c', 'd', 'e', 'f', 'g'):
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diff changeset
201 self.assertIn(key, dc)
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202 self.assertEqual(dc[key], 'v%s' % key)
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203
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204 # Original should remain unchanged.
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205 for key in ('a', 'b', 'c', 'd'):
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206 self.assertIn(key, d)
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diff changeset
207 self.assertEqual(d[key], 'v%s' % key)
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208
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209 def testpopoldest(self):
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210 d = util.lrucachedict(4)
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211 d.insert('a', 'va', cost=10)
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212 d.insert('b', 'vb', cost=5)
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213
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214 self.assertEqual(len(d), 2)
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diff changeset
215 self.assertEqual(d.popoldest(), ('a', 'va'))
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216 self.assertEqual(len(d), 1)
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217 self.assertEqual(d.totalcost, 5)
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218 self.assertEqual(d.popoldest(), ('b', 'vb'))
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219 self.assertEqual(len(d), 0)
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220 self.assertEqual(d.totalcost, 0)
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221 self.assertIsNone(d.popoldest())
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222
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223 d['a'] = 'va'
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224 d['b'] = 'vb'
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225 d['c'] = 'vc'
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diff changeset
226 d['d'] = 'vd'
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227
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228 self.assertEqual(d.popoldest(), ('a', 'va'))
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229 self.assertEqual(len(d), 3)
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230 for key in ('b', 'c', 'd'):
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diff changeset
231 self.assertEqual(d[key], 'v%s' % key)
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232
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233 d['a'] = 'va'
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234 self.assertEqual(d.popoldest(), ('b', 'vb'))
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235
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236 def testmaxcost(self):
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237 # Item cost is zero by default.
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238 d = util.lrucachedict(6, maxcost=10)
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239 d['a'] = 'va'
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240 d['b'] = 'vb'
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241 d['c'] = 'vc'
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242 d['d'] = 'vd'
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243 self.assertEqual(len(d), 4)
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244 self.assertEqual(d.totalcost, 0)
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245
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246 d.clear()
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247
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248 # Insertion to exact cost threshold works without eviction.
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249 d.insert('a', 'va', cost=6)
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250 d.insert('b', 'vb', cost=4)
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251
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252 self.assertEqual(len(d), 2)
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253 self.assertEqual(d['a'], 'va')
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254 self.assertEqual(d['b'], 'vb')
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255
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256 # Inserting a new element with 0 cost works.
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257 d['c'] = 'vc'
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258 self.assertEqual(len(d), 3)
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259
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260 # Inserting a new element with cost putting us above high
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261 # water mark evicts oldest single item.
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262 d.insert('d', 'vd', cost=1)
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263 self.assertEqual(len(d), 3)
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264 self.assertEqual(d.totalcost, 5)
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265 self.assertNotIn('a', d)
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266 for key in ('b', 'c', 'd'):
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267 self.assertEqual(d[key], 'v%s' % key)
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268
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269 # Inserting a new element with enough room for just itself
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270 # evicts all items before.
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271 d.insert('e', 've', cost=10)
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272 self.assertEqual(len(d), 1)
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273 self.assertEqual(d.totalcost, 10)
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274 self.assertIn('e', d)
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275
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276 # Inserting a new element with cost greater than threshold
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277 # still retains that item.
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278 d.insert('f', 'vf', cost=11)
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279 self.assertEqual(len(d), 1)
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280 self.assertEqual(d.totalcost, 11)
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281 self.assertIn('f', d)
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282
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283 # Inserting a new element will evict the last item since it is
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284 # too large.
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285 d['g'] = 'vg'
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286 self.assertEqual(len(d), 1)
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287 self.assertEqual(d.totalcost, 0)
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288 self.assertIn('g', d)
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289
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290 d.clear()
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291
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292 d.insert('a', 'va', cost=7)
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293 d.insert('b', 'vb', cost=3)
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294 self.assertEqual(len(d), 2)
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295
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296 # Replacing a value with smaller cost won't result in eviction.
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297 d.insert('b', 'vb2', cost=2)
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298 self.assertEqual(len(d), 2)
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299
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300 # Replacing a value with a higher cost will evict when threshold
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301 # exceeded.
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302 d.insert('b', 'vb3', cost=4)
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303 self.assertEqual(len(d), 1)
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304 self.assertNotIn('a', d)
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305
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306 def testmaxcostcomplex(self):
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307 d = util.lrucachedict(100, maxcost=100)
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308 d.insert('a', 'va', cost=9)
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309 d.insert('b', 'vb', cost=21)
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310 d.insert('c', 'vc', cost=7)
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311 d.insert('d', 'vc', cost=50)
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312 self.assertEqual(d.totalcost, 87)
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313
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314 # Inserting new element should free multiple elements so we hit
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315 # low water mark.
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316 d.insert('e', 'vd', cost=25)
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317 self.assertEqual(len(d), 2)
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318 self.assertNotIn('a', d)
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319 self.assertNotIn('b', d)
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320 self.assertNotIn('c', d)
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321 self.assertIn('d', d)
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322 self.assertIn('e', d)
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323
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2251b3184e6e util: add an LRU cache dict
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324 if __name__ == '__main__':
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325 silenttestrunner.main(__name__)